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# If a handover from TCH/H to TCH/F frees a dynamic timeslot,
# take the freed TCH/F from the soure timeslot into account,
# when the target is a static timeslot.
create-bts trx-count 1 timeslots c+s4 dyn TCH/F TCH/F TCH/F PDCH PDCH PDCH
network
bts 0
handover2 min-free-slots tch/f 2
handover2 min-free-slots tch/h 2
handover2 assignment 1
set-ts-use trx 0 0 states * TCH/H- - - - * * *
# (there must be at least one measurement report on each lchan for congestion check to work)
meas-rep lchan * * * * rxlev 40 rxqual 0 ta 0 neighbors 30
congestion-check
expect-ho from lchan 0 0 1 0 to lchan 0 0 2 0
expect-ts-use trx 0 0 states * pdch TCH/F - - * * *
# Again with one more TCH/F occupied, there will still be two free TCH/F after HO on the dyn TS
set-ts-use trx 0 0 states * TCH/H- - - TCH/F * * *
meas-rep lchan * * * * rxlev 40 rxqual 0 ta 0 neighbors 30
congestion-check
# FAIL: after the handover from the dyn TS to TCH/F, the dyn TS has freed a TCH/F, while the static TCH/F has reduced
# the TCH/F count by one. So the resulting free slots are 2 TCH/F, which means no congestion. A handover should occur.
expect-no-chan
# (TCH/H -> TCH/F onto a dyn TS will always make TCH/H congestion worse, so there is no useful test case left here)
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